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2.01x^2-26.64x+70=0
a = 2.01; b = -26.64; c = +70;
Δ = b2-4ac
Δ = -26.642-4·2.01·70
Δ = 146.8896
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26.64)-\sqrt{146.8896}}{2*2.01}=\frac{26.64-\sqrt{146.8896}}{4.02} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26.64)+\sqrt{146.8896}}{2*2.01}=\frac{26.64+\sqrt{146.8896}}{4.02} $
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